Description
Polymer Lipo Battery applications: Recording pen,Reading pen, Story machine, Early education machine MP3 MP4 MP5 , Bluetooth small speakers, Bluetooth glasses Miniature camera, tablet PC, music player, Mobile speaker, oudspeaker Driving recorder, Car keys, Locator, Phone, GPS Watch, Camera,MD,Digital cameras, Portable DVD Features: 1. Model: LP103048 2. Quantity: 1 3. Length: 48 mm Width: 30mm Thickness: 10 mm Capacity:1600 mAh 4. Rated voltage: 3.7V Charging voltage: 4.2V Charging temperature: 0 ° C to 45 ° C Discharge temperature: -20 ° C to + 60 ° C Storage temperature: -20 ° C to + 35 ° C Charging current: Standard charging: 0.5C , fast charge: 1.0C Standard charging method: 0.5C CC (constant current) charge to 4.25V, and then CV (constant voltage 4.2V) charge until the charge current ≤ 0.05C Maximum charge current: 1C Maximum discharge current: 1C Protection IC parameters: overcharge protection voltage 4.20V ± 0.05V, over discharge protection voltage 2.7V ± 0.1V, allow the maximum current 2A . Chemical composition: Lipo Battery 5.100% brand new high quality Li-polymer rechargeable battery 6. light weight, large capacity, no memory effect. 7. suitable for MID / PDA / bluetooth / mp3 / mp4 / reader backup power andother devices! 8. Built-in protection circuit PCM for prevent over charging or over discharging. 9. All our battery warranty for one year. 10. If you need bulk, please contact us, we will provide discount. 11. We will provide the tracking number. Warranty and Returns: All products have been checked and packaged in good condition beforedispatch. Item is defective in the case, after 30 days of receipt within, please inform us, we will replace a new one. Please do not open the dispute directly or leave negative feedback. Handling and transport: We will ship items in 1 working days of receipt of full payment. (Exceptweekend) Connections and services: We have your first feedback. We appreciate your positive feedback. If there is something unusual happens, please email us before leaving negative and neutral feedback. We will try to solve this problem.